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Firefox File Edit View History Bookmarks Tools Window Help MasteringPhysics: Homework 12 (Ch.11,12) e https://session.masteringphysics.com/myct/itemView?assignmentProblemID-80194632&offset.next; Homework 12 (Ch 11.12) Problem 12.48 Rosou Problem 12.48 Part A A copper block is removed from a 320 ° C oven and dropped into 1.20 kg of water at 22.0 C. The water quickly reaches 29.5 C and then remains at that temperature. The specific heats of copper and water are 385 J/(kg K) and What is the mass of the copper block? The specific heats of copper and water are 4190 J/(kg K) respectively. Express your answer to three significant figures and include the appropriate units. m= 1 Value Units Submit My Answers Give Up

Explanation / Answer

Solution:

As we know;

In this process the energy gained by water will be same as the energy lost by the copper block.

Here,

Energy gained by water is:

E = 4190 J/kgC x 1.2 kg x (29.5–22)0C

=> E = 37710 Joules

Energy lost by the copper block:

E = 385 J/kgC x M x (320–29.5)0C

=> E = 111842.5 x M Joules

Equating these two:

111842.5 x M = 37710

=> M = 0.33717 Kg

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