masteringphysics.com/myct/itemView? 78596911&offset; next Ch 21 HW Pat1Camot Cyc

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masteringphysics.com/myct/itemView? 78596911&offset; next Ch 21 HW Pat1Camot Cycle: Just How Ideal Is It? previous 4 of4 retum to assignment Carnot Cycle: Just How Ideal Is 1t? O A Camot engine would gonerate too much thermal pollution. Learning Goal To understand the quantitative relationships related to ideal (Camot) engines and the limitations of such devices imposed by the second law of Bulding the Camot angine is possible but e too expensive. The Camot engine has zero power The Camot engine has too low an eiciency In 1824, Sadi Carnot, a French engineer, introduced a heoretical engine that has been since then called a Carnot angine, the most efficient engine possible. The following statement is known as Camot's theorem No engine opera!ng between a hot and a oold reservoir can be more efficient than the Camot engine hat operates between the same two reservoirs The Carnot engine is a theoreical enginge with the maximum possible efficiency, somewhat like a "hought experiment. Sa a Camot engine operates cyclicaly just like any real engine.The Camot cycle includes four reversible steps: two isothermal processes and two sdiabatic ones Submit My Answers Give Up Correct The Camot surroundings at every shep, which makes it infinitely slow, therefore, the Camot powerful onel Its power is indeed zero, since work is being done at an infinitely slow rate cycle contains only reversible processes. To be reversible, a process must allow s r the system to equilibrate with its engine, although the most officient, is the least Part F A mal heat engine operates between temperatures T A mul hest engine operates between temperahures Ton andT and Ta During a certain time, an amount Q Duning a certain sime, an amount Qei o heat i elosedt to the col o that the engine might have performed? reservoir During that time, what is the maximum amount of work W Express your answer in terms of Qt Ts, and T Hints In this In this problem, you will be asked several questions about Canot engines. We will use the following symbols -Q the absolute value (magitude) of the heat absorbed from the hot reservoir during one cycle or during some time specified in the problem; out the absolute value (magnitude) of the heat delivered to the cold reservoir during one cycle or during some tme specified in the problem - W: the amount of work done by the engine during one cycle or during some time specified in the problem Tln: the absolube temperature of the hot reservoir, and My Answers Give Up Tost:the absolute temperature of the Incorrect: Try Again; 5 attempts remaining cold reservoir

Explanation / Answer

efficiency is eta = 1-(Tout / Tin) = Wmax/ Qout

then

(Tin - Tout)/Tin = Wmax/Qout

Wmax= [(Tin - Tout)*Qout] / Tin

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