1. An athlete performing a long jump leaves the ground at a 26.7 degree angle an

Question

1. An athlete performing a long jump leaves the ground at a 26.7 degree angle and lands 6.85 m away.
(a) What was the takeoff speed? (b) If this speed were increased by just 5.0%, how much longer would the jump be?
2. Suppose the rescue plane resleases the supplies at a horizontal distance of 427 m in advance of the mountain climbers.
(a) What vertical velocity should the supplies be given so that they arrive precisely at the climbers' position. (b) With what speed do the supplies land?

1. An athlete performing a long jump leaves the ground at a 26.7 degree angle and lands 6.85 m away.
(a) What was the takeoff speed? (b) If this speed were increased by just 5.0%, how much longer would the jump be?
2. Suppose the rescue plane resleases the supplies at a horizontal distance of 427 m in advance of the mountain climbers.
(a) What vertical velocity should the supplies be given so that they arrive precisely at the climbers' position. (b) With what speed do the supplies land?


(a) What was the takeoff speed? (a) What was the takeoff speed? (b) If this speed were increased by just 5.0%, how much longer would the jump be?
2. Suppose the rescue plane resleases the supplies at a horizontal distance of 427 m in advance of the mountain climbers.
(a) What vertical velocity should the supplies be given so that they arrive precisely at the climbers' position. (b) With what speed do the supplies land?

Explanation / Answer

1. (A) R = v0^2 sin(2 theta) / g

6.85 = v0^2 sin(2 x 26.7) / 9.8

v0 = 9.14 m/s

(b) v0' = 1.05 x 9.14 =9.60 m/s

R = 9.60^2 sin(2 x 26.7) / 9.8

R' = 7.55 m

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