General Physics Final Exam \"odt make your work clear to the grader show formula
ID: 1641285 • Letter: G
Question
General Physics Final Exam "odt make your work clear to the grader show formulas used. essential steps, and results with units and significant figures. Partial r your work is dear. Points shown in parenthesis credit is available l. is moon of Jupiter, with a mass M.&oa; 10 kg, and radius of km. 1820 a) NASA wants to put a satelite a very low orbit around lo, what orbital speed is needed? Che b) orbit's altitude is very small compared to lo's radius.) What period will this satellite have? 2 A 145 kg football player applies a force of 520 N hortzontaly on the opposing 125kg while pushing him backwards 3.3 m at constant speed before tackled. How much work did the tackler do while pushing? being e A2200-kg car is initially coasting at a speed of 24 ms when it comes to a "120 incline. It coasts without or air resistance, up the incine. a) How large is the initial kinetic energy of the car, in kJ? inkJ? Take the 75.0 the is the gravitational car, zero of PE to be at the bottom of the incine. potential energy of the coasting now after it went 75.0 m along the incline? his 850kg carts set in maton on a kovol road by a spring with spring constant k 2.40 10 Num that boen compressed 1.60 m. The car leaves the spring as passes point A and the driver siams on tho coefficiont 0,700 car a at point C, due to fiction with a) What is the inital mechanloatenergy of the system, with the spring comprossed 1.50 m, before car rolossed? b) car have wfen it leaves the spring at polntA? over what distance w the car skid to a stop after the brakes applied and the wheels areExplanation / Answer
3 )
a )
using kinetic energy is KE = 1/2 m v2
KE =1/2 X 2200 X 242
KE = 633600 J
b )
the height = h = L sin12
h = 15.6 m
PE = m g h
PE = 2200 X 9.8 X 15.6
PE = 336336 J
c )
using conservation of energy
1/2 m vo2 = m g h + 1/2 m v12
633600 = 336336 + 1/2 m v12
1/2 m v12 = 633600 - 336336
1/2 X 2200 X v12 = 633600 - 336336
v1 = 16.4 m/sec
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