A model rocket is launched with a very rapid engine burst. The engine cuts off q

Question

A model rocket is launched with a very rapid engine burst. The engine cuts off quickly and the rocket is subject only to gravity after that (ignore air resistance). At t = 0, (which we call height = 0) it is heading straight up with an initial speed of 54 m/s. We define "up" as the positive direction. Find its altitude at 1 s? Express your answer to two significant figures and include the appropriate units. h_1 = 60 m. Find its velocity at 7 s? Express your answer to two significant figures and include the appropriate units. v_7 = ________ ___________ Find its altitude at7 s?

Explanation / Answer

Given Data

At t = 0 , h = 0, inital speed , u = 54 m/s

Solution : -

Part - B) Altitude at t = 1 s is

h = ut - 0.5gt^2

h = 54*1 - 0.5*9.8*1^2

h = 54 - 4.9

h = 49.1 m

Parrt - C) velocity at 7 s is

v = u - gt

= 54 - 9.8*7

= -14.6 m/s

Parrt - D) altitude at 7 s is

h at 7 s = ut - 0.5gt^2

h at 7 s = 54*7 - 0.5*9.8*7^2

h at 7 s = 137.9 m

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