You are pushing a 5.15-kg box toward the right as it moves, in the direction of

Question

You are pushing a 5.15-kg box toward the right as it moves, in the direction of your push, over a patch of rough grass. Construct the free-body diagram for the box by correctly arranging the arrows in the diagram to the right. Each force acting on the box should be indicated by an arrow starting at the dot in the center of the box. Any arrow you don't use should remain entirely in the gray area at top. The arrows are labeled according to the following key: W = weight of box F = force of your push g = acceleration due to gravity N = normal force from ground f = friction force from grass If the magnitude of your push is 37.1 N, and the coefficient of kinetic friction with the grass is 0.350, What will be the magnitude and direction of the acceleration of the box?

Explanation / Answer

Given that,

m = 5.15 kg

F = 37.1 N

u = 0.35

Net force on the box,

Fnet = F - f

ma = F - uN = F - umg

a = (37.1 - 0.35*5.15*9.8) / 5.15

a = 3.77 m/s^2

direction of acceleration will be in positive x axis in the forward direction.

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