1. A 1.00-kg duck is flying horizontally overhead at 1.50 m/s when a hunter fire
ID: 1637178 • Letter: 1
Question
1. A 1.00-kg duck is flying horizontally overhead at 1.50 m/s when a hunter fires straight up. The 10-g bullet is moving vertically at a speed of 100 m/s when it hits the duck and stays lodged in the duck's body. What is the speed of the duck and bullet immediately after the hit?
a) 2.48 m/s
b) 1.49 m/s
c)1.80 m/s
d)1.36 m/s
e)1.78 m/s
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2. In an inelastic collision between two objects with unequal mass:
a) the total momentum of the system will decrease. the energy of one increases by the amount that the energy of the other decreases.
b) the velocity of one will increase by the amount that the velocity of the other decreases.
c) the kinetic energy of one will increase by the amount that the kinetic energy of the other decreases.
d) the momentum of one will increase by the amount that the momentum of the other decreases.
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3. A neutron in a nuclear reactor makes an elastic head-on collision with a carbon atom initially at rest. (The mass of the carbon atom is 12 times that of the neutron.) What fraction of the neutron's kinetic energy is transferred to the carbon atom? (i.e. Calculate the ratio of the final kinetic energy of the carbon atom to the initial kinetic energy of the neutron.
a) 41.4%
b) 14.2%
c) 56.8%
d) 34.6%
e) 28.4%
Explanation / Answer
Apply law of conservation of momentum in x direction
md udx + mb ubx = ( md+mb) vx
vx = md udx/(md + mb)
= 1(1.5)/(1+0.01)
=1.485 m/s
in y axis
md udy + mb uby = ( md+mb) vy
vy = mb uby/(md + mb)
= 0.01(100)/(1+0.01)
=0.99 m/s
magnitude of velocity
v = sqrt vx^2 + vy^2
= sqrt ( 1.485^2 + (0.99)^2
= 1.78 m/s
option ( e) is correct answer
(2)
the momentum of one object will increase by the amount that the momentum of the other object deecreases
As per guide lines I worked first two questions
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