According to the value above, how to find the absolute uncertainty in spring con

Question

According to the value above, how to find the absolute uncertainty in spring constant?

A249.3 t 129 g mass is hung from the end of a spring. The spring is pulled down 2.20 t 0 30 cm and released A stopwatch is used to measure the time it takes the spring to oscillate 10 times, 10T (ie from max height to min height and back to max height ten times). This is repeated another 2 times The measurements are recorded below. 10 T (s) trial 1 6.26 trial 2 5.98 trial 3 6.00 What is the period for a single oscillation? 0.608 The correct answer is: 0.608 What is the uncertainty in the period? 0014 Correct The correct answer is 0,014 What is the spring constant k for the spring? 26.6 Correct The correct answer is 26.6 What is the absolute uncertainty in the spring constant? x Nm

Explanation / Answer

As w = (k/m)1/2

2/T = (k/m)1/2

k = 42m/T2

So

k/k = m/m + 2T/T

k = k(m/m + 2T/T) = (26.6){(0.0129/0.2493) + 2(0.014/0.608) = 2.60141

k = 2.60141 N/m

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