You are standing in a spaceship. With respect to an observer in a given frame of
ID: 1636217 • Letter: Y
Question
You are standing in a spaceship. With respect to an observer in a given frame of reference, how fast would the spaceship have to move in order for your [moving] mass to be double your resting mass? From your perspective, what will be your mass onboard the spaceship?
In the last three weeks we have investigated time, length, and mass at very high velocities. Identify the unifying physical principle that ties all three of these investigations together and explain how they are connected.
Use the following equation for relativistic mass to solve this problem and submit your answer to the Week 4 assignment page. Make sure to show how you arrived at your answers. If you need assistance or have any questions please post in the Course Questions Help Forum on the course homepage.
Equation for relativistic mass:
Where:
m = the relative mass of a moving object
m' = the mass of the object at rest
v = the velocity of the object
c = the speed of light
You are standing in a spaceship. With respect to an observer in a given frame of reference, how fast would the spaceship have to move in order for your [moving] mass to be double your resting mass? From your perspective, what will be your mass onboard the spaceship?
In the last three weeks we have investigated time, length, and mass at very high velocities. Identify the unifying physical principle that ties all three of these investigations together and explain how they are connected.
Use the following equation for relativistic mass to solve this problem and submit your answer to the Week 4 assignment page. Make sure to show how you arrived at your answers. If you need assistance or have any questions please post in the Course Questions Help Forum on the course homepage.
Equation for relativistic mass:
Where:
m = the relative mass of a moving object
m' = the mass of the object at rest
v = the velocity of the object
c = the speed of light
Explanation / Answer
m = mo / (1 - v2 /c2 )
given m = 2 mo
2 mo = mo / (1 - v^2 /c^2 )
1/4 = (1 - v^2 /c^2 )
v^2/c^2 = 3/4
thus speed of spaceship, v = (3)c/2 or 2.598 * 108 m/s
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