I have an answer, but I\'d like to feel more confident in it. Please show your w

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I have an answer, but I'd like to feel more confident in it. Please show your work, I'd like to interact with you in the comments if I don't get it.
2. Consider a simplified model of a triply ionized beryllium9 atom (Be); four protons plus five neutrons in the atoms nucleus, "orbited" by just one electron at a constant distance of 450 x 10m. (Note: This is not the actual distance, but it is near the correct order of magnitude.) (6 pts.) You can solve (a) &(b) in either order. Label your work clearly: a. What is the strength (magnitude) of the attractive electrie force between the nucleus and the electron? Show your work b. What is the magnitude of the electrie field at the electron's location? Is its direction toward or away from the nucleus? Show your work. c. (3 pts.) What is the strength (magnitude) of the attractive gravitational force between the nucleus and the electron? (Recall: Fe=GmiMy / , ) Show your work. d. (I pt.) For this particular nucleus and orbiting electron, how many times stronger is the electric force in part (a) than the gravitational force in part (c)? Divide and find out: (You do NOT need to show your work.) . Thought question (not for credit) When chemists deal with the interaction forces between atoms, is it valid for them to consider only electrical forces (ionic bonds, hydrogen bonds, dipole interactions, van der Waals forces, etc.) while ignoring gravitational forces?

Explanation / Answer

a) F = k q1 q2 /r^2 = 9 x 10^9 ( 4 x 1.6 x 10^-19 ) ( 1.6 x 10^-19) / (4.5 x 10^-12)^2=4.55 x 10^ -5 N apprx

b)E = kq/r^2 = 9 x 10^9 (4 x 1.6 x 10^-19) / ((4.5 x 10^-12)^2= 2.844 x 10^ 14 N/c outward from neucleus

c)F = G mM /r^2 =

mass of nucleus= 6.8e-27 kg.

F = 6.67 x 10^-11 ( 6.8 x 10^-27 ) (9.109 x 10^-31)/ (4.5 x 10^-12)^2= 20.402 x 10^-45 N

d) ratio:Fe/Fg = 4.55 x 10^ -5 / 20.402 x 10^-45= 22.3 x 10^ 38apprx

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