Two point charges are placed on a horizontal line, the first is +2.0-uC located

Question

Two point charges are placed on a horizontal line, the first is +2.0-uC located at x = 0.0-m, y = 00-m and the second is-3.0 m, y = 0.0-m. At what points on the horizontal line y = 0.0 will the electric potential be zero? C located at x = 1.0- In the following four boxes, enter your x positions in meters, from most positive to least positive. There are not necessarily four positions of zero potential. Enter zero for any remaining boxes. Example: if you found the electric potential was zero atx = 12, 0.5 and-1 m; you would enter 11.21 10.51 1-11 101 into the four boxes. Most positive Least Positive Check

Explanation / Answer

The position of 0 potential will occur between teh charges and to the left of positive charge,

1) V1 + V2 = 0 ( for position between charges)

K ( 2x 10^-6)/ ( x) + K (-3x 10^-6) /( 1-x) =0

2/ x = 3/ (1-x)

2 - 2x= 3x

5x = 2

x= 0.4 m from origin,

b) to the left of positive charge,

K ( 2 x 10^-6) / ( x) + K ( -3 x 10^-6) / ( 1+x) =0

2/x= 3/(1+x)

2+2x= 3x

2= x

( to the left of origin , so it should be -2 m)

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