The magnetic field of a proton is very similar to that of a circular current loo
ID: 1635310 • Letter: T
Question
The magnetic field of a proton is very similar to that of a circular current loop 0.650 × 10-15 m in radius carrying 1.05 × 104 A. An MRI machine is required to be able to manipulate these fields.
(a) To see why an MRI utilizes iron to increase the magnetic field created by a coil, calculate the current needed in a 400 loop-per-meter circular coil 0.660 m in radius to create a 1.20 T field (typical of an MRI instrument) at its center with no iron insert. No Answer Given
(b) What is the field at the center of a proton? Notice how it compares to the field we used in the previous calculation. No Answer Given
Explanation / Answer
(a) We know that the magnetic field of solenoid
B = uoNI /L
here N/L = 400
Magnetic field = 1.2 T
1.2 = (4Pi*10-7)*(400)*I
I = 2.387*103 A
(b) Magnetic field at the center of loop
B = (uo*I / 2*r ) = (4Pi*10-7)*(1.05*104) /(2)*0.65*10-15
B = 1.015*1013 T
Now we compare
B/BMRI = 1.015*1013 /1.2 = 8.458*1012
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