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7/28/2017 10:55 PM @Time Remaining: 52M75 Gradebook uestion 2 of 5 The character

ID: 1634407 • Letter: 7

Question

7/28/2017 10:55 PM @Time Remaining: 52M75 Gradebook uestion 2 of 5 The character Walverine (see picture density, high-strength metal alloy called Adamantium, which has the following ) has had all of his bones replaced with a high- Map d - A density of 7.90 A specific heat of 0.470 J/g-K -A coefficient of inear expansion of 13.6x 10-6/C Ler's consider his left femure to be a cylinder with the following properties when Wolverine is at rest Aradus of 1.25 am .Alength of 50.5 A mass of 1980 g a certain fight, Wolverine's core body temperature increases Answer the three questions below, using three signfcant fgures Part A: What is the change in length (L) of his femure given the tempurature change his body experiences from 38.0 to 396 Number cm Part B: How much thermal energy (AETh) does the femure absorb during the tempurature change? Number O Previous O Next Save And Exit rning, Inc

Explanation / Answer

Given , density of adamantium, rho = 7.9 g/cm^3
specific heat, C = 0.470 J/g K
coefficient of linear expansion, alpha = 13.6*10^-6 C

consdier his femur
radius, r = 1.25 cm
length, l = 50.5 cm
mass, m = 1980 g

temperature change, dT = 39.6 - 38 = = 1.6 K

A. change in length due to thermal heating
   dL = L(alpha(dT))
   dL = 50.5(13.6*10^-6*1.6) = 1.0988 mm
B> enegy absorbed by the material, E = mCdT
   but mass = m = density*Volume
   Volume = pi*r^2l
   m = rho*pi*r^2*l = 7.9*pi*1.25^2*50.5 = 1958.341 grams
   E = 1958.341(0.470*1.6) = 1472.672 J
C. thermal volume expansion coefficient is three times the linear expaqnsion coefficeint
so the answer is
3

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