Map do Sapling Learning quite right. He thinks he can model the slingshot like a

Question

Map do Sapling Learning quite right. He thinks he can model the slingshot like an Tom has built a large slingshot, but it is not ideal spring, with a constant of 75.0 N/m. he pulls the back 0.375 m from a non- telling him to aim for an elastic with a higher spring constant. By what factor does Tom need to increase the spring constant to hit his position, it just doesn't launch its payload as far as he wants. His physics professor helps energy of 14.5 Joules. Tom he just needs elastic bands and try pullin before must Tom pull the slingshot back to hit the potential energy goal with the original spring constant? ulling the sli many times further than In which of the two scenarios does Tom have to pull harder? O O They Are Equal Increased Spring Constant

Explanation / Answer

(1)

Potential energy function

U = (1/2) kx2

14.5 J = (1/2) k (0.375)2

k = 206.22 N/m

Deciding this by original spring constant to get factor

206.22/75 = 2.75

(2)

U = (1/2) kx2

14.5 J = (1/2)(75)x2

x = 0.622

Deciding by original x to get the factor

0.622/0.375 = 1.66

(3)

Increase spring constant

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