A) Two point charges, the first with a charge of +3.39×10 6 C and the second wit

ID: 1632065 • Letter: A

Question

A) Two point charges, the first with a charge of +3.39×106 C and the second with a charge of -4.34×106 C , are separated by 23.5 cm .

Find the magnitude of the electrostatic force experienced by the positive charge.

B) Given that q = +10 C and d = 15 cm , find the magnitude of the net electrostatic force exerted on the point charge q2 in the figure. (Figure 1)

q1= +q q2=-2.0 q q3= +3.0q

https://session.masteringphysics.com/problemAsset/2337479/1/Walker.19.15.jpg

Express your answer using two significant figures.

Find the direction of the net electrostatic force exerted on the point charge q2 in the figure.

Part C

How would your answers to part A and B change if the distance d were tripled?

F= N

A) Force on positive charge = (9*109*3.39*10-6*4.34*10-6)/0.2352

= 2.4 N

B) Force on q2 due to q1 = (9*109*10*10-6*20*10-6)/0.152

= 80 N(towards left)

Force on q2 due to q3 = (9*109*30*10-6*20*10-6)/0.152

= 240 N(towards right)

Therefore, net force on q2 = 240-80 = 160 N(towards right)

C) part A :Force on positive charge = (9*109*3.39*10-6*4.34*10-6)/(3*0.235)2

= 0.267 N

part B : Force on q2 due to q1 = (9*109*10*10-6*20*10-6)/(3*0.15)2

= 8.89 N(towards left)

Force on q2 due to q3 = (9*109*30*10-6*20*10-6)/(3*0.15)2

= 26.67 N(towards right)

Therefore, net force on q2 = 26.67-8.89 = 17.78 N(towards right)

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