7/17/2017 11:55 PM O 65.7/1007/17/2017 02:59 PM Gra CalaulatorPeriodic Table ues

Question

7/17/2017 11:55 PM O 65.7/1007/17/2017 02:59 PM Gra CalaulatorPeriodic Table uestion 14 of 23 Incorrect Incorect Sapling Learning Map A flat 138-tum current-carrying loop is immersed in a uniform magnetic field. The area of the loop is 5.99 x10 m2 and the angle between its magnetic dipole moment and the field is 35.9. Find the strength of the magnet of doo 95 A flows in it tic field that causes a torque of 1.39 ×10° N, m to act on the loop when a arrent Number 0896 There is a hint availablel botlom divider the on divider bar again to hide the hint Close O Prevous Check Answer 0 Next Ext | about us careers privacy policy terms of help F3 F4 FS F7

Explanation / Answer

N = 138 ; A = 5.99 x 10^-4 m^2 ; theta = 35.9 deg ; T = 1.39 x 10^-5 N-m ; I = 0.00295

We know that the torque acting in the magnetif field is given by:

T = N B I A sin(theta)

B = T/(N I A sin(theta))

B = 1.39 x 10^-5 / [138 x 0.00295 x 5.99 x 10^-4 x sin35.9] = 0.0972 T

Hence, B = 0.0972 T = 97.2 mT

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