A rectangular coil with 5 turns of width = 0.300 cm and length = 0.500 cm has a

Question

A rectangular coil with 5 turns of width = 0.300 cm and length = 0.500 cm has a total resistance of 5 W. It moves with velocity = 3.12 m/s into a uniform magnetic field of 54.6 mT as shown. (a) what is the magnitude and direction of the current induced in the loop as it enters the B field.

(b) What is the force on the loop (magnitude and direction) as it enters the field.

(c) What is the force on the loop while it is completely within the B field? (d) What is the direction of the induced current as it leaves the field?

(d) Several hours after the current reaches its maximum value, the battery fails - producing no voltage, but keeping the circuit connection closed. Will there be current in the circuit? If so, in what direction will it flow? Explain your answer.

Explanation / Answer

a )

the current is

i = B w v / R

= 54.6 X 10-3 X 0.3 X 10-2 X 3.12 / 5

i = 1.022 X 10-4 A

direction of induced current is in anticlockwise

b )

F = i w B

F = 1.022 X 10-4 X 0.3 X 10-2 X 54.6 X 10-3

F = 1.67 X 10-8 N

direction is into the right side

c )

the loop while it is completely within the B field then force willbe zero

d )

the direction of induced current is clockwise

e )

the induced current is same

and

direction is in anti-clockwise

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