The Fate of an Electron in a Uniform Electric Field In this problem we will stud

Question

The Fate of an Electron in a Uniform Electric Field In this problem we will study the behavior of an electron in a uniform electric field. Consider a uniform electric field E magnitude E) as shown in the figure within a parallel plate capacitor in vacuum. ho First, let us review the relationship between an electric field and its associated electric potential V. For now, ignore the electron located between the plates. Part A Calculate the electric potential V(h) inside the capacitor as a function of height h. Take the potential at the bottom plate to be zero. Express V(h) in terms of E and h Hints V(h) =

Explanation / Answer

A) V(h) = Eh

B) electron's potential energy = qV = -qeEho

C) conserving energy,

0.5mv2 + (-qeEh1) = -qeEho

v = sqrt[2(qeEh1 - qeEho)/m] = sqrt[2qeE(h1 - ho)/m]

D) kinetic energy of electron = qeE(h1 - ho) = kinetic energy of heavy particle

=> Kheavy/Ke = 1

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