A roller coaster starts from rest at the top of an 18-m hill as shown. The car t

Question

A roller coaster starts from rest at the top of an 18-m hill as shown. The car travels to the bottom of the hill and continues up the next hill that is 10.0 m high.

a. How fast is the car moving at the top of the 10.0-m hill, if friction is ignored?

b. how fast is the car moving at the flat portion of the ride, if friction is ignored?

c. Because in the real world friction DOES exist consider the following…..If friction on the track now does -1500 J of work on the cart that has a mass of 150 kg. Calculate the velocity of the cart at the flat portion of the ride.

A roller coaster starts from rest at the top of an 18-m hill as shown. The car travels to the bottom of the hill and continues up the next hill that is 10.0 m high.

a. How fast is the car moving at the top of the 10.0-m hill, if friction is ignored?

b. how fast is the car moving at the flat portion of the ride, if friction is ignored?

c. Because in the real world friction DOES exist consider the following…..If friction on the track now does -1500 J of work on the cart that has a mass of 150 kg. Calculate the velocity of the cart at the flat portion of the ride.

Explanation / Answer

Applying law of conservation of energy at at the top of two hills

Mgh=mgh1+(1/2)mv^2

Here v= speed of particle at height of 10m

h=18m,h1=10m

V=sqrt(2g(h-h1))

=12.52m/s

B)if friction is ignored it moves at a speed at flat surface Is

V=sqrt(2gh)

=79.7m/s

C)applying law of conservation of energy we get

Mgh= work done by friction+(1/2)mv^2

(150*9.8*18)-1500=0.5*150v^2

On solving we get 182 m/s

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