A cannonball is fired from the ground at an angle theta with an initial speed v_
ID: 1630080 • Letter: A
Question
A cannonball is fired from the ground at an angle theta with an initial speed v_0. If the cannon the cannonball lands back at the same height it was launched from (neglect air resistance): a.) For how long will the cannonball be in the air? b.) How far will it travel horizontally? c) What is the speed of the ball at the highest point in the trajectory? d) What is the maximum height reached by the ball? GIVE ALL ANSWERS IN TERMS OF theta, v_0, AND g. v AND g REMEMBER TO SEPARATE YOUR WORK INTO TWO COLUMNS FOR HORIZONTAL AND VERTICAL MOTION OF THE PROJECTILE!Explanation / Answer
Take Vo=u
y=usintheta×t+1/2gt^2
b) horizontal distance x=ucos theta×t
V=usin theta -gt
At highest point V=0
usin theta =gt
t=usin theta/g
a)Total time =2 usin theta/g
C)at highest point velocity wil be zero
D) max height
V^2-u^2=-2gs
-u2sin^2 theta=-2gh
h=u2sin2theta/2g
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