The highlighted part I can\'t seem to answer Correctly Two capacitors C_1 = 4.6
ID: 1628471 • Letter: T
Question
The highlighted part I can't seem to answer Correctly
Two capacitors C_1 = 4.6 mu F, C_2 = 14.2 mu F are charged individually to V_1 = 13.8 V, V_2 = 6.5. The two capacitors are then connected together in parallel with the positive plates together and the negative plates together. Calculate the final potential difference across the plates of the capacitors once they are connected. Ca Calculate the amount of charge (absolute value) that flows from one capacitor to the other when the capacitors are connected together. By how much (absolute value) is the total stored energy reduced when the two capacitors are connected? Calculate the stored energy for the two capacitors individually before they were connected and add them up, and compare that to the energy of the combined system.Explanation / Answer
Solution:
Change in enrgy stored in the system of capacitors = initial indivisual energies - final energy stored in the whole system
=> Reduce energy or change in energy, U = (1/2×C1×V12 + 1/2×C2×V22) - (1/2×Ceq×Vnet2)
=> U = (1/2×4.6×10-6×13.82 + 1/2×14.2×10-6×6.52) - 1/2×(4.6+14.2)×10-6×8.2862
=> U = 92.604×10-6 J
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