Vector d_1 is in the negative direction of a y axis, and vector d_2 is in the po
ID: 1628449 • Letter: V
Question
Vector d_1 is in the negative direction of a y axis, and vector d_2 is in the positive direction of an x axis. What are the directions of (a) d_2/7 and (b) d_1/(-7)? What are the magnitudes of products (c) d_1 middot d_2 and (d) d_1.(d_2/7)? what is the direction of the vector resulting from (a) d_1 times d_2 and (f) d_2 times d_1? What is the magnitude of the vector product in (g) part(e) and (h) part (f) what are the (i) magnitude and (j) direction of d_1 times (d_2/7), (Use the following notation: d_1 is the magnitude of the vector d_1, d_2 is the magnitude of vector d_2.)Explanation / Answer
(A) d2/7 will be in same direction as d2.
so along positive x axis.
(B) d1 / (-7) will be in opposite direction of d1.
that is positive direction of y.
(c) d1.d2 = |d1||d2| cos(theta)
theta = 90 deg
cos90 = 0
d1.d2 = 0
(d) 0
(e) d1 - > -j
d2 -> i
d1 x d2 -> -j x i = - (-k) =k
along positive z axis.
(f) d2 x d1 - > i x -j = - k
along negative z axis
(g) d1 d2
(h) d1 d2
(i) d1 d2 / 7
(j) positive z direction
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