2. Let the mass of the solid spherical moon be 7.0E22 kg and radius 1500 km. Let

Question

2. Let the mass of the solid spherical moon be 7.0E22 kg and radius 1500 km. Let it make one spin in 20 days and one spin generates 6.28 radians. What is the moment of inertia on the moon? A. 6.3E28 kg.m^2 B. 6.3E34 kg.m^2 C. 6.3E22 kg.m^2 D. None E. 6.3E40 kg.m^2
3. What is the spin angular speed of the moon? A. 0.314 rad/s B. 2.17E-4 rad/s C. 0.0131 rad/s D. None E. 3.63E-6 rad/s
4. What is the KE of the moon due to spin motion? A. None B. 4.16E23 N/m^2 C. 2.29E29 J D. 4.26E23 N E. 3.63E-6 rad/s
5. A geostationary satellite appears to remain stationary for an observer from the Earth. True or False? Question Completion Status: Question 1 2 points save Answ the mass of the Earth be ME 6.0 x 1024 kg and the mass the Moon MM be 7.0 x 1022 kg, and if the Earth-Moon distance be rEarth. of Moon is 300,000 km. find the force of attraction between the two bodies. a. 3.11E26 N b. 3.11E20 N c 3.11E32 N d 4.46E36 N e none Question 2 2 points Save Answer Let the mass of the solid spherical Moon be 70E22 kg and radius 1500 km. Let it one spin 20 days and one make in what is the moment of inertia of the moon? 63E28 kg m 63E34 kg.m2 none 6.3E22 kg.mi 6.3E40 kg m Question 3 2 points What is the spin angular speed of the Moon? 0.314 rad/s b 2.18E-4 rad/s CO,0131 rad/s d. none e 3.63E-6 rad/s. s

Explanation / Answer

1) Given,

Mass of earth, me = 6 x 1024 kg

Mass of moon, mm 7 x 1022 kg

Distance, r = 3 x 108 m

Force of attraction, F = G Me Mm / r2

  = (6.67 x 10-11) ( 6 x 1024) ( 7 x 1022) / ( 3 x 108)2

F = 3.11 x 1020 N

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