210-Polonium is the last radioactive element in the 238-U decay chain. (via what

Question

210-Polonium is the last radioactive element in the 238-U decay chain. (via what kind of emission?) lt can also be produced in reactors by neutron irradiation of Bismuth. 210-Po has a half-life of 138 days. 209 210At 211 At 212 21 At At About how many alpha particles per Po 209 Po 210 Po 211 21 208 second are emitted by 1 ug of 210-Po? Decays per second is activity and has 207Bi 208Bi 209Bi 10Bi 21 SI unit of Becquerel. Atraditional unit is the Curie: 3.7 x 10 1 Ci. 206pb Pb 208pb 209pb 21 A. 6.0 x 23 Bq 205 208 20 207 B. 1.7 x 11 Bq C. 3.8 x 10 Bq D. 1.7 x 108 Bq NA 6 x 23 /mol 1.7 x 108 Bq 4.5 mCi-quite a bit

Explanation / Answer

We know activity of any radioactive material is given by

A=N*decay constant

where N is undecayed nucleus of element

here m=1*10^(-6)

no of moles=1*10^(-6)/210

N=no of moles*6.023*10^23=2.86*10^(15)

decay constant=ln2 /half life in seconds =5.8*10^(-8)

so we got

A=1.66*10^(8) Bacqueral

so (D) is correct

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