A 200-turn coil with an average radius of 0.06 m is placed in a uniform magnetic

Question

A 200-turn coil with an average radius of 0.06 m is placed in a uniform magnetic field so that ø = 30 degrees. The strength of the field increases at a rate of 0.450 T/s. What is the magnitude of the resulting emf? Please show your work and steps, and thank you in advance! A 200-turn coil with an average radius of 0.06 m is placed in a uniform magnetic field so that ø = 30 degrees. The strength of the field increases at a rate of 0.450 T/s. What is the magnitude of the resulting emf? Please show your work and steps, and thank you in advance!

Explanation / Answer

use,
emf=N*d(flux)/dt

emf=N*d(B.A*cos(theta))/dt

emf=N*A*cos(theta)*dB/dt

emf=200*(pi*0.06^2)*cos(30)*0.45

emf=0.88 V

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