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According to our records you have not yet redeemed an access code for this class or purchased access online. The grace period will and Tuesday. June 20 2017 at 12 00 AM CDT After that dale you will no longer be able to see your WebAssign assignments or grades Get access now. The velocity vs. time graph for an object moving along a straight path is shown in the figure below. (i) Find the average acceleration of this object during the following time Intervals. (a) 0 s to 5.0 s _ m/s^2 (b) 5.0 s to 15 s _ m/s^2 (c) 0 s to 20 s m/s^2 (ii) Find the instantaneous accelerations at the following times. (a) 2.0 s: m/s^2 (b) 10 s m/s^2 (c) 18 s _m/s^2 A ball is thrown directly downward with an initial speed of 7.60 m/s, from a height of 30.6 m. After what time interval does it strike the ground? _S

Explanation / Answer

a)

here

average acceleration = delta v / delta t

= (vf - vi)/(tf - ti)

from 0s to 5s

average acceleration is = (-8 -(-8)) / (5 - 0) = 0m/s^2

b)

from 5s to 15s

average acceleration is = (8 - (-8)) / (15 - 5) = 1.6 m/s^2

c)

from 0s to 20s

average acceleration is = (8 - (-8)) / (20 - 0) = 0.8 m/s^2

ii)

a) for 2sec

instantaneous acceleration = delta v/ delta t = (-8 -(-8)) / (5 - 0) = 0m/s^2

b)

for 10sec

instantaneous acceleration is = (8 - (-8)) / (15 - 5) = 1.6 m/s^2

c)

for 18sec

instantaneous acceleration is = (8 - 8) / (20 - 15) = 0 m/s^2

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