For question B, what does r stand for? And for e4 and e5 why is it 10^-5 and not
ID: 1626895 • Letter: F
Question
For question B, what does r stand for? And for e4 and e5 why is it 10^-5 and not 10*10^-6 and lastly for r^ potion on the equation what exactly is going on.
Please help 25%. oo T-Mobile Wi-Fi 20:00 pdf (3).pdf Done PHY 2049 Exam 1 Name & PID Spring 2015 Problem 25 points) Im Consider the rectangular charge distribution shown in the figure to the right. The five point charges with charge Q +10HC are held in place. Im So (a) (10 points) Determine the electric potential atthe point P Im KG Im 3 4 in im Vs 3.97 x ros volts b)(15 points) Determine the electric field at the point P E, E. E Ea an E. Canal & r. 3.18 ')(16%) KEQ 9x, ID Cim) So Go FIU PHY 2049 Exam 1 Name & PID
Explanation / Answer
The formula for potential due to point charge is V= kq/r so what they are actually doing is that they are finding the potential due to the given 5 point charges (each 10uC) at the given point. This Q= 10uC and r1,r2,r3,r4,r5 are the respective distances of each of the point charges from the point we are calculating the potential. And K is constant which has value 9 x 109 and Nm2/C2 is its unit just as length has unit of meter(m).
In part B it is same but here we are calculating a vector quantity electric field whereas potential is a scalar quantity. We cannot directly add vectors. So we are trying to superimpose these vectors. r is the distance of point from where you are calculating field and r cap means it is a position vector of the charge. E4 and E5 are the field due to charge number 4 and 5 respectively. Also 10-5 is same as 10 x 10-6 so whichever you write is correct.
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