a) Calculate the period of oscillation for a pendulum of 4m b) A pendulum with m

Question

a) Calculate the period of oscillation for a pendulum of 4m b) A pendulum with mass M and length L is released as a small angle off of vertical and oscillates with period P. If we double the mass and halve the length of the pendulum, what is the new period? Explain. Setup and solve the equation that expresses the gravitational force between two 80kg adults, separated by 2m. Find: Free body diagrams Equations of for each block The acceleration of each block Tension in the string Position of M_a after .5s Velocity of M_a after .5s

Explanation / Answer

Q.2 a) Time period of simple pendulum = 2pi sqroot ( L/g) = 2x3.14 sqroot ( 4/ 9.8) = 4.01 sec apprx

b) Time period is independent of mass and depends only upon length and gravity

P = 2pi sqroot ( L/g)

if we halve the length ( L/2), new period would be = 2pi sqroot ( L/2g) = 2pi / sqoot (2) { P}

= pi sqroot ( 2) P ----------new time period

Q: 3 F = G m1 m2/ r^2

F = 6.67 x 10^-11 ( 80)^2 / 2^2= 1.0672 x 10^-7 N apprx ( ypu can round off0

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