In a practice, a football players runs the pattern shown above. Leg A is 3 meter

Question

In a practice, a football players runs the pattern shown above. Leg A is 3 meters long, leg B is 14 meters long and leg C is 20 meters long. The angle phi between legs B and C is 41 degree. (Legs A and B are perpendicular.) What is the magnitude of the displacement of the football player from her original position? |A + B + C| = What is the value of theta? theta = What is x component of her displacement? (Assume the x direction to be horizontal on that drawing above.) (A + B + C)_x = What is y component of her displacement? (Assume the y direction to be vertical on that drawing above.) (A + B + C)_y =

Explanation / Answer

A+B+C= 3 j + 14 i+ 20cos41 i - 20 sin41 j

= 29.09 i -10.12 j

1) Magnitude = Sqrt( 29.09^2+10.12^2) = 30. 8 m

2) Angle theta= tan^-1(10.12/29.09)= 19.18 degrees

3) 29.09 m (right)

4) 10.12 (down)

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