Tired of being chased by the jaguar, you set a trap. Hoping to drop it on the ja

Question

Tired of being chased by the jaguar, you set a trap. Hoping to drop it on the jaguar, you try to push a 44.0 kg stone boulder off of the edge of a cliff that slopes down at an angle of 15.0 degree. Being weak with hunger, the best you can do is push the boulder with a force of 222 N. The coefficient of kinetic friction between the boulder and the ground is 0.700. (Ignore static friction.) A) What is the acceleration of the boulder while you push it down the incline? B) Can you drop the boulder off the edge of the cliff? Why or why not?

Explanation / Answer

Force on boulder due to gravity,

Fg = mgsin(theta)

Force due to friction,

Fr = uN = umgcos(theta)

Net force on boulder,

Fnet = Fg + Fr

Fnet = F + mgsin(theta) - umgcos(theta)

Acceleration of boulder,

a = Fnet / m

a =  F/m + gsin(theta) - ugcos(theta)

a = (222 / 44) + 9.8*sin15 - 0.7*9.8*cos15

a = 0.956 m/s^2

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