+q . . . . . . . . . . . . . . . . -q |<--------- d ---------->| Two charges +q
ID: 1624045 • Letter: #
Question
+q . . . . . . . . . . . . . . . . -q
|<--------- d ---------->|
Two charges +q and -q are at distance d apart, as indicated above, and the force between them has magnitude F.
The left hand charge is now doubled and made negative, becoming -2q, and the right hand charge remains the same, at the same position.
Which of the following best describes the forces now, in terms of the original force F?
Select one:
a. Force on the left hand charge is 2F to the left and the force on the right hand charge is 2F to the right.
b. Force on left-hand charge is 2F to the right and the force on the right-hand charge is F to the left.
c. Force on left-hand charge is 2F to the left and the force on the right hand charge is F to the left.
d. Force on left-hand charge is 2F to the right and the force on the right-hand charge is 2F to the left.
e. Force on left-hand charge is 2F to the right and the force on the right-hand charge is 2F to the right.
Which ONE of the following is INCORRECT?
Select one:
a. If one K+ leaves the cell and one Na+ enters at the same time, membrane potential will remain the same
b. If many K+ channels AND many Na+ channels were open at rest, the cell would find it difficult to maintain a resting membrane potential
c. Due to the relatively large number of open K+ channels, the number of K+ entering the cell equals the number of K+ leaving the cell
d. If a K+ leaves the cell, the inside of the cell becomes a little more negative.
e. The urge for Na+ to enter the cell is very great – both concentration gradient and membrane potential attracts Na+ entry
Explanation / Answer
Force two chareged particles is
F= kq2 / r2
since the magnitude of charge on the left is doubles, the force on left is 2F to the right and the force on right is F to the left.
Answer is 'b'
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