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An object 0.50 cm high is 5.0 cm from a concave spherical mirror of focal length

ID: 1622981 • Letter: A

Question

An object 0.50 cm high is 5.0 cm from a concave spherical mirror of focal length 20 cm. How high is the image and is it erect or inverted? A) 0.50 cm, inverted B) 0.67 cm, inverted C) 0.40 cm, erect D) 0.40 cm, inverted E) 0.67 cm, erect. The clear water of a lake is 1.95 m deep at the end of a dock, You look directly down from the end of the dock and see a rock on the bottom of the lake. How far below the surface does the rock appear to be? (For water, n = 1.33.) A) 1.47 m B) 0.733 m C) 2.59 m D) 0.689 m E) 2.93 m A diverging lens has a focal length of magnitude 18 cm. An object is placed 10 cm in front of the diverging lens. Calculate the magnification of the image and whether it is upright or inverted. A) 0.85 inverted B) 1.5 upright C) 0.64 inverted D) 0.52 upright E) 0.64 upright Two side-by-side coherent light sources radiate at 633 nm. At a point in space where the path difference to these two sources is 30 nm, the phase difference is A) 0.324 radians B) 0.356 radians C) 0.298 radians D) 0.429 radians E) 0.238 radians Light of wavelength 640 nm is incident perpendicularly from air onto a film 1000 nm thick and of refractive index 1.65. When part of the light enters the film and is reflected back at the second face, the number of wavelengths contained along the path of this light in the film is A) 5.16 B) 1.56 C) 3.13 D) 2.58 E) 1.29 Light of wavelength 500 nm illuminates parallel slits and produces an interference pattern on a screen that is 1 m from the slits. In terms of the initial intensity I_0, the intensity of the light in the interference pattern at a point for which the path difference is 100.nm is A) 0.382 I_0 B) 2.62 I_0 C) 0.655 I_0 D) 1.62 I_0 E) 0.618 I_0 The bending of light around an obstacle such as the edge of a slit is called A) reflection B) refraction C) dispersion D) diffraction E) polarization

Explanation / Answer

29.
= Real Depth/Apparent Depth
thus
Apparent depth= 1.95/1.33= 1.46m (Ans)

34. Diffraction

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