A new particle accelerator facility is being built. The designers are considerin

Question

A new particle accelerator facility is being built. The designers are considering two designs, one using stationary targets and the other using collisions of beams with the same energy.

Part A

Consider a beam of protons with energy 211.0 GeV . If these protons collide with stationary protons, what is the available energy Ea in a collision?

Express your answer in billions of electron volts to three significant figures.

Part B

Now, consider two beams of protons, moving in opposite directions, each with energy 106 GeV . What is the available energy Ea when these beams collide?

Express your answer in billions of electron volts to three significant figures.

Explanation / Answer

a)

Using

The total available energy = 2 ( mpc2 +Ek)
= 2 (1.627 x 10-27 * 9 x 1016 + 211)
= 2 (14.643 x 10-11J + 211)
= 2 ( 14.643 x 6.242 x 107 eV + 211)
= 424GeV
b)
The total available energy = 2 ( mpc2 +Ek)
= 2 (1.627 x 10-27 * 9 x 1016 + 106)
= 2 (14.643 x 10-11J + 106 )
= 2 ( 14.643 x 6.242 x 107 eV + 106 )
= 214GeV

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