A student bikes to school by traveling first d N = 0.800 milesnorth, then d W =

Question

A student bikes to school by traveling first dN = 0.800 milesnorth, then dW = 0.300 miles west, and finally dS = 0.100 miles south.

Part A

Take the north direction as the positive y direction and east as positive x. The origin is still where the student starts biking. Let d N be the displacement vector corresponding to the first leg of the student's trip. Express d N in component form.

A student bikes to school by traveling first dN = 0.800 milesnorth, then dW = 0.300 miles west, and finally dS = 0.100 miles south.

Part A

Take the north direction as the positive y direction and east as positive x. The origin is still where the student starts biking. Let d N be the displacement vector corresponding to the first leg of the student's trip. Express d N in component form.

Explanation / Answer

vertical components = 0.8 - 0.1 = 0.7
horizontal components = 0.3
0.3^2^2 + 0.7^2 = d^2
d = 0.761miles
angle = inv tan ( 0.3 / 0.7 ) = 23.198 deg west of north.
so component

0.761miles 23.198 deg west of north ....Ans

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