A mass 2Kg rests against a spring of an unknown constant. You have measure the c

Question

A mass 2Kg rests against a spring of an unknown constant. You have measure the coefficient of friction to be 0.15. If the spring has been compressed by 10cm and acceleration measured for the block is 15m/s/s without friction A. Find the spring constant B. Find how far the travels before having an acceleration of 0 m/s/s. C. Find the total distance traveled by the Block as it comes to rest. Physics experiment still wrong. You have made it back to the mid-1700s and changed to help create a submersible. The wooden assemble has a dry mass of 550Kg, resembles a cylinder that floats with 25% above the waterline. A. Find the mass of water needed pumped in such that only 5% is above the water line. B. Find the mass of water needed pumped in such that it is neutrally buoyant. Colossal collisions. (Figure 2) A Storm Giant is playing a game shuffle board with the local wizards towers. Tower 1 is slid across the frozen lake with a velocity of 15m/s and has a mass of 3 times 10^4 Kg. Tower 2 is twice the mass but not moving. After the first collision the two towers are stuck together. They travel on toward the third tower that has three times the mass of tower one. The wizard tries to move her tower out of the way but chooses the wrong direction and moves instead at a velocity of 1.5m/s towards the two towers. She raises her wards the towers bounce off each other. Find: The velocity of the two towers after the first collision. B: The velocity of the two tower and the velocity of the third towers after they bounce. A Harpsichord has a string made of steel that is 2.3 meters effective. If the tension is such that the string has the 87^th harmonic, and the velocity is 45m/s. A. Find the Wavelength of the wave on the string. B. Find the Frequency of the wave. C. Find the mass the string if the Tension is 500 N D. Find the new Frequency if the string were heated to 50 degrees above room temp.

Explanation / Answer

(5)(a) Fs- Ff= ma

Fs= spring force= kx and Ff= force of friction= u mg

kx- u mg= ma

k(0.1)- 0.2 (2)(9.8)= 2 (15)

k= 239.2 N/m.

(b)if a=0,

kx- u mg= ma

239.2 x-0.2 (2)(9.8)= 2 (0)

239.2 x=3.92

x=0.0164 m

x= 1.64 cm.

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