My Notes Ask Your Teacher (a) A 2.20 cm high insect is 1.23 m from a 135 mm foca

Question

My Notes Ask Your Teacher (a) A 2.20 cm high insect is 1.23 m from a 135 mm focal-length lens. What is the image distance? 15.2 x mm How high is the image? .27 x crm What type is it? (Select all that apply.) The image is behind the lens. The image is real. O The image is in front of the lens. O The image is inverted. O The image is upright. O The image is virtual (b) What if f 135 mm? What is the image distance? 122 x mm How high is the image? .22 Cm What type is it? The image is upright. The image is virtual. O The image is in front of the lens. The image is behind the lens. The image is inverted. The image is real

Explanation / Answer

Please try these answer.

(a)
Ho = 2.2 cm
Do =1.23 m
F = 135 mm = 0.135 m
F is positive it is a convex lens
(1/F) = (1/Do) + (1/Di)
Di = 0.1434 m =143.4 mm
M = - Hi / Ho = - Di / Do
Hi = 0.2564 cm

since Di is positive and M is negative
The image is real, inverted located on the other side of the lens

(b)
F = - 135 mm = - 0.135 m
F is negative so it is a concave lens
(1 / - 0.135) = (1/1.23) + (1/Di)
Di = - 0.1216 m
Hi = + 0.2175 cm

since Di is negative and M is positive
The image is virtual upright located on the object side

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