So I\'ve found the acceleration of the CM to be 2.95m/s^2, using a=(fpush-fricti

Question

So I've found the acceleration of the CM to be 2.95m/s^2, using a=(fpush-friction force)/total mass. Both blocks being the system. However for this assignment I need to relate dp/dt=fnet to the solution for acceleration. I've tried using the relation fnet= (m*v)/t= dp/dt. Is there any way I can further relate fnet=(m*v)/t=dp/dt to my solution of a=(fpush-friction force)/total mass?

Figure 5.71 P15 In Figure 5.72 m 12 kg and m2 5 kg. The kinetic coefficient of friction between mu and the floor is 0.3 and that between m2 and the floor is 0.5. You push with a force of magnitude F 110 N. (a) What is the acceleration of the center of mass? (b) What is the magnitude of the force that ml exerts on m2? mil m2. Figure 5.72

Explanation / Answer

F net = dP/dt = d ( mv - mu)/ dt

Fnet = m d ( v-u) / dt

F push - Frictional force = m d ( v-u) /dt

110 - ( 0.3 x 12x 9.8 + 0.5 x 5 x 9.8 ) = ( 17 ) a ( where d( v-u) /dt = a)

110 - 59.78 = 17 (a)

a= 2.95 m/s^2

b)

Force exerted by m1 on m2 - force of fiction = m2 (a)

Force exerted by m1 on m2= 5 (2.95 ) + 0.5 ( 5) (9.8) = 39.25 N

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