Just need the answers. A 1.0 cm high object sits on the optic axis 40 cm to the
ID: 1618837 • Letter: J
Question
Just need the answers. A 1.0 cm high object sits on the optic axis 40 cm to the left of a lens, which is diverging with a focal length of - 120 cm. What (magnitude of) distance is the image from the lens? (a) 20 cm (b) 30 cm (c) 75 cm (d) 120 cm (e) 180 cm By what factor is the image magnified? (a) 1/3 (b) 2/3 (c) 3/4 (d) 1 (e) 3/2 characterize the image, as to its reality, its orientation, & its location relative to the lens. (a) real, inverted, on the left (b) real, inverted, on the right (c) real, erect, on the right (d) virtual, erect, on the left (e) virtual, inverted, on the left Sketch out a ray tracing diagram locating the image. Suppose that a second f_2 = 460 - cm lens is placed along the optic axis 80 cm to the right of the first lens. Then what is the location of the final image from the second lens? (a) 40 cm left (b) 60 cm right (c) 90 cm left (d) 120 cm right (e) 180 cm right Characterize the image, as to its reality, its orientation, & its location relative to the lens. (a) real, inverted, on the left (b) real, inverted, on the right (c) real, erect, on the right (d) virtual, erect, on the left (e) virtual, inverted, on the leftExplanation / Answer
43.
using lens formula
1/v-1/u=1/f
u=-40,f=-120
v=-30
manitude of the distance of image from the lens is 30 cm
44.magnification m=v/u=-30/-40 =3/4
45. the image is virtual erect and to the left of the lense because mis positive
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