Just need the answers. A ray of red light with wavelength 680 nm travels in air
ID: 1618836 • Letter: J
Question
Just need the answers. A ray of red light with wavelength 680 nm travels in air to make an angle of incidence of 50 degree at a surface of a pool of water (with index of refraction = 1.33, while that of air is 1.00). (a) 16 degree (b) 22 degree (c) 33 degree (d) 50 degree (e) 65 degree What is the angle of refraction in the water? (a) 19 degree (b) 26 degree (c) 35 degree (d) 44 degree (e) 59 degree What is the speed of light in the water? (a) 330 m/s (b)700mi/hr (c) 140,000 mi/hr (d) 2.3 times 10^8 m/s (e) 3 times 10^8 m/s What is the wavelength of this light in the water? (a) 350 nm (b) 420nm (c) 510nm (d) 610nm c) 800nm What is the frequency of the light in the water? (a) 330 Hz (b) 1500Hz (c) 140,000Hz (d) 4.4 times 10^14 Hz (e) 6.8 times 10^15 HzExplanation / Answer
38. angle of reflection = angle of refraction
= 50 deg
Ans(d)
39. Snell's law, ni sin(i) = nr sin(r)
sin50 = 1.33 sin(r)
r = 35 deg
Ans(c)
40. v = c / n = ( 3 x 10^8) /1.33 = 2.3 x 10^8 m/s
Ans(d)
41. lamdba = 680 nm / 1.33 = 511 nm
Ans(c)
42. f = c / lambda
f = (3 x 10^8) / (680 x 10^-9)
= 4.4 x 10^14 Hz
Ans(d
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