Two small loudspeakers are separated by a distance of d = 5.5 cm, as shown in th

Question

Two small loudspeakers are separated by a distance of d = 5.5 cm, as shown in the figure below. The speakers are driven in phase with a sine wave signal of frequency 20 kHz. A small microphone is placed a distance L = 1.60 m away from the speakers on the axis running through the middle of the two speakers, and the microphone is then moved perpendicular to the axis. Where does the microphone record the first minimum and the first maximum of the interference pattern from the speakers? The speed of sound in air is 343 m/s. y_1st min = 37.4 cm y_1st max = cm

Explanation / Answer

d = 5.5 cm , f =20 kHz, L =1.6 m,

v =343 m/s

for constructive interference condition: dsin(theta) = m*lamda , m =0,1,2 ..

for destructive interference condition: dsin(theta) = (m+0.5)*lamda , m =0,1,2 ..

v = f*lamda

lamda = v/f = 343/20000 = 0.02144 m

(theta)max =arcsin(lamda/d)

(theta)max =arcsin(0.02144/0.055)

(theta)max = 23 degrees

ymax = Ltan(theta)max = 1.6*tan(23) =0.6792 m

ymax = 67.92 cm

(theta)min =arcsin(lamda/2d)

(theta)min =arcsin(0.02144/(2*0.055))

(theta)max = 11.24 degrees

ymin = Ltan(theta)min = 1.6*tan(11.24) =0.318 m

ymin = 31.8 cm

ymax = 67.92 cm

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