In an x ray tube, the electrons are accelerating through a 4.0 kV potential diff

Question

In an x ray tube, the electrons are accelerating through a 4.0 kV potential difference. What can be concluded regarding the wavelengths) of the emitted rays?

A. no conclusion about the wavelength(s) is possible without more information.
B. the peak wavelength is around 0.3nm, but there are both larger and smaller wavelengths present
C. the wavelength is about 0.3nm
D. the maximum wavelength is about 0.3nm
E. the minimum wavelength is about 0.3nm
F. the range of wavelengths is about 0.15nm to 0.3nm
G. the range of wavelengths is about 0.3nm to 0.6nm

Explanation / Answer

The minimum wavelength calculation is given by

wavelength=12;398/V

V is poyential difference in kilovolts

wavelength=12.398/4=3.09 A=3.09*10^(-10)

wavelength=0.309*10^(-9)=0.3 nm

so shortese wavelength=0.3nm

so (E) is correct

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