can someone please solve Q2 real fast.Thank you A 10.0 g marble sides to the lef

Question

can someone please solve Q2 real fast.Thank you

A 10.0 g marble sides to the left with a velocity magnitude o 550 mws on the frictionless, hortzontal icy, New sliding to the right with a velocity of magnitude 0.250 mis head larger 20.0-0 (a) Find the velocity of each marble (magnitude direction) ater the colision. (since the collision and motion is right as the positive direction. (b) Calculate the change momentum (that is, the momentum after the colisen minus the momentum before the collsion) for each marble (c) Calculate the change energy (that is, the kinetic energy after the collsion menus the kinetic energy before the collision) for each marble

Explanation / Answer

in an elestic collision

v1 = (m1-m2)u1+2m2u2/(m1+m2)

v1 = 0.01*0.55+2*0.02*0.25/0.03 = 0.517 m/s

v2 = 2m1u1+(m2-m1)u2/(m1+m2)

v2 = -2*0.01*0.55+0.01*0.25/0.03 = -0.283 m/s

b) change in momentum

p1f-p1i = 0.01(0.517+0.55) =0.0106 kg m/s

p2f-p2i = 0.02(-0.283-0.25) = -0.0106 kg m/s

c) k1f-k1i = -0.000176 J

k2f-k2i = 0.000176 J

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