A group of students performed an experiment where two carts were rolled toward e
ID: 1616670 • Letter: A
Question
A group of students performed an experiment where two carts were rolled toward each other to cause a collision. Data collected from this experiment is graphed below.
a. By how much does the total momentum decrease as a result of the collision.
b. What force was most likely responsible for the decrease in momentum?
c. Assume the carts are moving at the same velocity after the collision.
i. Calculate the ratio: MassCart A / MassCart B
ii. Which cart has the greater kinetic energy before the collision? Justify your answer.
Cart B 0.1 0.2 0.3 0.4 -1 Time (s) AB rt rt CC 011 O 4 3 2 1 0 2 (s/lu.ay) unueuuowExplanation / Answer
The initial momentum iis pi = 3 -1 = 2 kg m/s
Final momentum is pf = 1 + 0.5 = 1.5 kg m/s
the change in momentum is pf - pi = 2 - 1.5 = 0.5 kg m/s
b)
The change in momentum could be due to the friction force.
c)
1) The ratio of the momentum after collision is
PA / PB = 1.5 / 2
MA V / MB V = 1.5 /2
MA / MB = 0.75
2) The kinetic energy is directly proportional to the square of the momentum.
KA / KB = ( PA2/PB2 ) ( MB /MA)
= ( 9 / 1 ) ( 1/0.75) = 12
The kinetic energy of mass A is 12 times greater then mass B
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