You have a lens of focal length 15 cm that will be used for the eyepiece of a Ne

Question

You have a lens of focal length 15 cm that will be used for the eyepiece of a Newtonian telescope. You wish th telescope to have a magnifying power of 18x. A) What focal length lens do you need for the objective? B) What will be the length of your telescope? Light passing through a diffraction grating with the slits separated by 0.01 mm. The light is of waveler and the interference pattern is projected onto a screen 0 m from the diffraction grating. A) What is the angle that corresponds to the first (m=1) bright spots on either side of the central (m=0) B) How far apart is the (m = 0) central bright spot and the first (m = 1) bright spots on the wall?

Explanation / Answer

(11) ans

Given that

magnifying power =18

focal length of the eye piece fe=15 cm

basing on the ray optices and telescope

now we find the focal length of the objective

magnifying power =fo/fe

18=fo/15

fo=270 cm

therefore the focal length of the objective fo=270 cm

now we find the length of the telescope

the length L=fo+fe=270+15=285 cm

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