During a back rub, 82 g of ethanol is converted from a liquid to a gas. Part A D

Question

During a back rub, 82 g of ethanol is converted from a liquid to a gas.
Part A Determine the thermal energy removed from a person's body by this conversion. Assume that the rubbing alcohol vaporizes directly. Heat of vaporization at the boiling temperature for ethanol is Lv= 0.854x10^6 J/kg. During a back rub, 82 g of ethanol is converted from a liquid to a gas.
Part A Determine the thermal energy removed from a person's body by this conversion. Assume that the rubbing alcohol vaporizes directly. Heat of vaporization at the boiling temperature for ethanol is Lv= 0.854x10^6 J/kg.
Part A Determine the thermal energy removed from a person's body by this conversion. Assume that the rubbing alcohol vaporizes directly. Heat of vaporization at the boiling temperature for ethanol is Lv= 0.854x10^6 J/kg.

Explanation / Answer

Energy removed will be given by:

E = m*Lv

Using the given values:

m = 82 gm = 0.082 kg

Lv = 0.854*10^6 J/kg

So,

E = 0.082*0.854*10^6 = 70028 J

E = 70.028 kJ

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