. You throw a rubber ball at a downward angle so that when it hits the ground, t

ID: 1615302 • Letter: #

Question

You throw a rubber ball at a downward angle so that when it hits the ground, the ball bounces off

with the same speed with which it hit the ground. How could you increase the impulse the ground

exerts on the ball by the collision (assume you always throw the ball at the same initial speed)?

A.Since the ball's speed does not change as a result of the collision, the impulse exerted on it

by the ground is the same regardless of how it is thrown.

B.By throwing the ball at a steeper angle (i.e. so its initial velocity is closer to being directly

down).

C.Since the ball's speed does not change as a result of the collision, the impulse exerted on it

by the ground is always 0 Ns.

D.By throwing the ball at a shallower angle (i.e. so its initial velocity is farher from being

directly down).

E.By throwing the ball at the same angle with respect to the vertical but directed above the

horizontal.

Answer is B, can you please explain in detail why? Thanks

ball is thrwoing in vertical direction so when ball bounce horizontal component is cancel out

impulse = chnage in momentum

p = mvsintheta - (-mvsintheta)

p = 2mvsintheta

if angle is steeper then sin theta is maximum

p = 2mv

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