The radius of curvature of a spherical concave mirror is 11 cm. When an object i

Question

The radius of curvature of a spherical concave mirror is 11 cm. When an object is positioned 8 cm from the mirror, what is the image distance? Follow the sign convention. (Express your answer to two significant figures.) When a 10-cm-tall object is positioned 8 cm from the mirror, what is the image height? Follow the sign convention. (Express your answer to two significant figures.) When an object is positioned 8 cm from the mirror, is the image real or virtual? real virtual When a 10-cm-tall object is positioned 8cm from the mirror, is the image upright or inverted? upright inverted When an object is positioned 23 cm from the mirror, what is the image distance? Follow the sign convention. (Express your answer to two significant figures.) When a 10-cm-tall object is positioned 23 cm from the mirror, what is the image height? Follow the sign convention. (Express your answer to two significant figures.) When an object is positioned 23 cm from the mirror, is the image real or virtual? real virtual When a 10-cm-tall object is positioned 23 cm from the mirror, is the image upright or inverted? upright inverted When a 10-cm-tall object is positioned 190 cm from the mirror, what is the image distance? Follow the sign convention. (Express your answer to two significant figures.)

Explanation / Answer

a) r=11 cm

We have the spherical mirror equation 1/o +1/i =2/r where o is the object distance, i is the image distance and r is the radius of curvature of the spherical mirror.

Here we have, o=8 cm.

Substituting these values in the above equation we obtain, i=17.6 cm.

b) Magnification m=-i/o

We have o=8 cm, r=11 cm, i=17.6 cm

Therefore, m=17.6/8=2.2 cm.

Height of image=2.2*10=22 cm.

c) Image is real following the sign convention for spherical mirrors.

d) Image is inverted since the magnification m is negative.

e) We have 1/i=2/11 -1/23=35/253

i=7.2 cm

f)Inverted

g) 1/i=2/11-1/190=0.18

i=5.7 cm

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