T/F please answer all of them. 1. ( ) Typical capacitors have a capacitance rang

Question

T/F please answer all of them.

1. ( ) Typical capacitors have a capacitance ranging from pF to mF, which means when it is connected to a battery of 1 Volt, it will only store a “small” amount of charge ranging from 10-12 C to 10-6C.

2. ( ) When an uncharged capacitor is connected to a battery (that means each plate is connected to one terminal of the battery), charges start to flow to “charge” the capacitor, until the voltage difference between the two plates are equal to the potential difference between the battery’s terminals. The two plates will have the same amount of charges with opposite sign.

3. ( ) Consider a capacitor consisting of two parallel plates. The E field in between the two plates is nearly uniform. Hence E=DV/d, where E is the E field strength, DV is the voltage difference (potential difference) between the two plates, and d is the separation (distance) between the two plates.

4. ( ) Consider a capacitor consisting of two parallel plates. When it is kept being connected to a battery, it will maintain a fixed value of DV, if you increases the distance (separation) between the two plates the E field will be decreased.

5. ( ) Consider a capacitor consisting of two parallel plates. At equilibrium the, E field strength between the two plate is E=s/(2e0), where s is Q/Area, the charge density on the plate. (Check example 24.5 on page 734 to verify, Figure 24.15)

6. ( ) Consider a capacitor consisting of two parallel plates. At equilibrium the, E field strength between the two plate is E=s/e0, where s is Q/Area, the charge density on the plate. Because both plates are charged, the E field is twice of the E field due to one charged plate. Or when you consider Gauss’s Law, outside of the capacitor has no E field, the E field Flux is only on one side, (EA=Q/e0 ), E=Q/(Ae0)(Check example 24.5 on page 734 to verify, Figure 24.15)

7. ( ) Consider a capacitor consisting of two parallel plates. E=DV/d and E=Q/(2Ae0), hence Q/(2Ae0) = DV/d. So the ratio between Q and DV is Q/DV=(2Ae0) /d. The capacitance C= Q/DV=(2Ae0) /d, is determined by the area of the plate and the distance in between them.

8. ( ) Consider a capacitor consisting of two parallel plates. E=DV/d and E=Q/(Ae0), hence Q/(Ae0) = DV/d. So the ratio between Q and DV is Q/DV=(Ae0) /d. The capacitance C= Q/DV=(Ae0) /d, is determined by the area of the plate and the distance in between them

9.( ) Consider a capacitor consisting of two parallel plates. It is charged already with +Q on one plate and –Q on the other plate. It is then isolated and not connected to anything else, so the charges will not move anywhere. Now if we increase the distance between the two plates, the E field in between the two plates will decreases.

10.( ) Consider a capacitor consisting of two parallel plates. It is charged already with +Q on one plate and –Q on the other plate. It is then isolated and not connected to anything else, so the charges will not move anywhere. Now if we increase the distance between the two plates, the E field in between the two plates will stay the same, since E is only determined by the charge density s, which is not changed (Q and A are not changed).

11. ( ) Consider a capacitor consisting of two parallel plates. It is charged already with +Q on one plate and –Q on the other plate. It is then isolated and not connected to anything else, so the charges will not move anywhere. Now if we increase the distance between the two plates, the E field in between the two plates will stay the same, but the voltage difference between the two plates will increase, side DV=Ed. Also C=Q/ DV will decreases.

12.( ) The capacitance of a capacitor is determined by its shape, size and separation distance. For a capacitor with two parallel plates, its capacitance increases when the plate area increases.

13.( ) The capacitance of a capacitor is determined by its shape, size and separation distance. For a capacitor with two parallel plates, its capacitance increases when the plate area decreases.

14.( ) The capacitance of a capacitor is determined by its shape, size and separation distance. For a capacitor with two parallel plates, its capacitance increases when the plate separation distance increases.

15.( ) The capacitance of a capacitor is determined by its shape, size and separation distance. For a capacitor with two parallel plates, its capacitance increases when the plate separation distance decreases.

16.( ) When two capacitors are in connected parallel, the will have the same voltage difference. And the total charges stored will be the sum of the charged stored in each capacitor. Ceq =Qtotal / DV = (Q1 + Q1)/ DV, hence the total capacitance is the sum of C1 & C2.

17.( ) When two capacitors are in connected series, the will have the same voltage difference. And the total charges stored will be the sum of the charged stored in each capacitor. Ceq =Qtotal / DV = (Q1 + Q1)/ DV, hence the total capacitance is the sum of C1 & C2.

18.( ) When two capacitors are in connected parallel, the must have the same charge, which is also the equivalent total charge. And the total voltage difference will be the sum of the voltage difference across in each capacitor. Ceq =Q/ DVtotal = Q/ (DV1+ DV2), hence the total capacitance can be calculated using the reversed sum of C1 and C2. For capacitors in parellel, 1/Ceq = 1/C1 +1/C2

19.( ) When two capacitors are in connected series, the must have the same charge, which is also the equivalent total charge. And the total voltage difference will be the sum of the voltage difference across in each capacitor. Ceq =Q/ DVtotal = Q/ (DV1+ DV2), hence the total capacitance can be calculated using the reversed sum of C1 and C2. For capacitors in series, 1/Ceq = 1/C1 +1/C2

20.( ) When resistors are in series, the total resistance is the sum of the individual resistance. When resistors are in parallel, the reverse of the equivalent resistance, is the sum of the reverse of individual resistance.

21.( ) Capacitors are like resistors when combined. When capacitors are in series, the total capacitance is the sum of the individual capacitance. When capacitors are in parallel, the reverse of the equivalent capacitance, is the sum of the reverse of individual capacitance.

22.( ) Capacitors have opposite properties comparing to resistors when combined. When capacitors are in parallel, the total capacitance is the sum of the individual capacitance. When capacitors are in series, the reverse of the equivalent capacitance, is the sum of the reverse of individual capacitance.

Explanation / Answer

1. ( ) Typical capacitors have a capacitance ranging from pF to mF, which means when it is connected to a battery of 1 Volt, it will only store a “small” amount of charge ranging from 10-12 C to 10-6C.

FALSE

2. ( ) When an uncharged capacitor is connected to a battery (that means each plate is connected to one terminal of the battery), charges start to flow to “charge” the capacitor, until the voltage difference between the two plates are equal to the potential difference between the battery’s terminals. The two plates will have the same amount of charges with opposite sign.

TRUE

3. ( ) Consider a capacitor consisting of two parallel plates. The E field in between the two plates is nearly uniform. Hence E=DV/d, where E is the E field strength, DV is the voltage difference (potential difference) between the two plates, and d is the separation (distance) between the two plates.

TRUE

4. ( ) Consider a capacitor consisting of two parallel plates. When it is kept being connected to a battery, it will maintain a fixed value of DV, if you increases the distance (separation) between the two plates the E field will be decreased.

TRUE

5. ( ) Consider a capacitor consisting of two parallel plates. At equilibrium the, E field strength between the two plate is E=s/(2e0), where s is Q/Area, the charge density on the plate. (Check example 24.5 on page 734 to verify, Figure 24.15)

FALSE

6. ( ) Consider a capacitor consisting of two parallel plates. At equilibrium the, E field strength between the two plate is E=s/e0, where s is Q/Area, the charge density on the plate. Because both plates are charged, the E field is twice of the E field due to one charged plate. Or when you consider Gauss’s Law, outside of the capacitor has no E field, the E field Flux is only on one side, (EA=Q/e0 ), E=Q/(Ae0)(Check example 24.5 on page 734 to verify, Figure 24.15)

TRUE

7. ( ) Consider a capacitor consisting of two parallel plates. E=DV/d and E=Q/(2Ae0), hence Q/(2Ae0) = DV/d. So the ratio between Q and DV is Q/DV=(2Ae0) /d. The capacitance C= Q/DV=(2Ae0) /d, is determined by the area of the plate and the distance in between them.

FALSE

8. ( ) Consider a capacitor consisting of two parallel plates. E=DV/d and E=Q/(Ae0), hence Q/(Ae0) = DV/d. So the ratio between Q and DV is Q/DV=(Ae0) /d. The capacitance C= Q/DV=(Ae0) /d, is determined by the area of the plate and the distance in between them

TRUE

9.( ) Consider a capacitor consisting of two parallel plates. It is charged already with +Q on one plate and –Q on the other plate. It is then isolated and not connected to anything else, so the charges will not move anywhere. Now if we increase the distance between the two plates, the E field in between the two plates will decreases.

FALSE

10.( ) Consider a capacitor consisting of two parallel plates. It is charged already with +Q on one plate and –Q on the other plate. It is then isolated and not connected to anything else, so the charges will not move anywhere. Now if we increase the distance between the two plates, the E field in between the two plates will stay the same, since E is only determined by the charge density s, which is not changed (Q and A are not changed).

TRUE

11. ( ) Consider a capacitor consisting of two parallel plates. It is charged already with +Q on one plate and –Q on the other plate. It is then isolated and not connected to anything else, so the charges will not move anywhere. Now if we increase the distance between the two plates, the E field in between the two plates will stay the same, but the voltage difference between the two plates will increase, side DV=Ed. Also C=Q/ DV will decreases.

TRUE

12.( ) The capacitance of a capacitor is determined by its shape, size and separation distance. For a capacitor with two parallel plates, its capacitance increases when the plate area increases.

TRUE

13.( ) The capacitance of a capacitor is determined by its shape, size and separation distance. For a capacitor with two parallel plates, its capacitance increases when the plate area decreases.

FALSE

14.( ) The capacitance of a capacitor is determined by its shape, size and separation distance. For a capacitor with two parallel plates, its capacitance increases when the plate separation distance increases.

FALSE

15.( ) The capacitance of a capacitor is determined by its shape, size and separation distance. For a capacitor with two parallel plates, its capacitance increases when the plate separation distance decreases.

TRUE

16.( ) When two capacitors are in connected parallel, the will have the same voltage difference. And the total charges stored will be the sum of the charged stored in each capacitor. Ceq =Qtotal / DV = (Q1 + Q1)/ DV, hence the total capacitance is the sum of C1 & C2.

TRUE

17.( ) When two capacitors are in connected series, the will have the same voltage difference. And the total charges stored will be the sum of the charged stored in each capacitor. Ceq =Qtotal / DV = (Q1 + Q1)/ DV, hence the total capacitance is the sum of C1 & C2.

FALSE

18.( ) When two capacitors are in connected parallel, the must have the same charge, which is also the equivalent total charge. And the total voltage difference will be the sum of the voltage difference across in each capacitor. Ceq =Q/ DVtotal = Q/ (DV1+ DV2), hence the total capacitance can be calculated using the reversed sum of C1 and C2. For capacitors in parellel, 1/Ceq = 1/C1 +1/C2

FALSE

19.( ) When two capacitors are in connected series, the must have the same charge, which is also the equivalent total charge. And the total voltage difference will be the sum of the voltage difference across in each capacitor. Ceq =Q/ DVtotal = Q/ (DV1+ DV2), hence the total capacitance can be calculated using the reversed sum of C1 and C2. For capacitors in series, 1/Ceq = 1/C1 +1/C2

TRUE

20.( ) When resistors are in series, the total resistance is the sum of the individual resistance. When resistors are in parallel, the reverse of the equivalent resistance, is the sum of the reverse of individual resistance.

TRUE

21.( ) Capacitors are like resistors when combined. When capacitors are in series, the total capacitance is the sum of the individual capacitance. When capacitors are in parallel, the reverse of the equivalent capacitance, is the sum of the reverse of individual capacitance.

FALSE

22.( ) Capacitors have opposite properties comparing to resistors when combined. When capacitors are in parallel, the total capacitance is the sum of the individual capacitance. When capacitors are in series, the reverse of the equivalent capacitance, is the sum of the reverse of individual capacitance.

TRUE

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