A conducting bar of length l moves to the right on two frictionless rails as sho

Question

A conducting bar of length l moves to the right on two frictionless rails as shown in the figure below. A uniform magnetic field directed into the page has a magnitude of 0.320 T. Assume R = 8.80 Ohm and l = 0.340 m. (a) At what constant speed should the bar move to produce an 8.30-mA current in the resistor? m/s (b) What is the direction of the induced current? clockwise counterclockwise into the page out of the page (c) At what rate is energy delivered to the resistor? mW (d) Explain the origin of the energy being delivered to the resistor.

Explanation / Answer

induced emf e = l v B

l is length = 0.34 m

v is speed = ?

B is magnetic field = 0.32 T

induced current I = emf/R = l v B/R = 8.3 *10^-3

R is Resistance

so

0.34 *v * 0.32/8.8 = 8.3*10^-3

v = 0.671 m/s

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b.

from Lenz law

indcued emf and Current opposes the actual direction of motion of the conductire

so here this is

COUNTER CLOCK WISE direction

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c. POWer P = i^2 R

P = 8.3 *10^-3 * 8.3 *10^-3 * 8.8

P = 0.606 mW

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