Consider a bar, of length m, shown in the figure, being acted on by three forces

Question

Consider a bar, of length m, shown in the figure, being acted on by three forces. The magnitudes of the first two forces are 28 N and 21 N. and the first force is acting on the end of the bar at an angle of as 59 degree shown. What is the torque, in newton-meters, due to F_1 on this bar relative to the left end? Use a coordinate system with positive directed out of the screen. Numeric A numeric value is expected and not an expression tau_1 = What is the torque, in newton-meters, due to F_2 on this bar relative to the left end, if this force is acting at the midpoint of the bar? Use a coordinate system with positive directed out of the screen Numeric A numeric value is expected and not an expression. Tau_2 = What is the magnitude of the force F_3, in newtons, if the force is a distance 0.65 m from the left end and the bar is not rotating? Numeric A numeric value is expected and not an expression. F_3 =

Explanation / Answer

a) Torque due to F1, relative to left end = F1*d*sin(59)

= 28*4.5*sin(59)

= 108 N.m

b) Torque due to F2, relative to left end = F2*(d/2)*sin(90)

= 28*(4.5/2)*1

= 63 N.m

c) Apply, Net torque = 0

T1 + T2 - T3 = 0

108 + 63 - F3*x*sin(90) = 0

F3 = (108 + 63)/x

= (108 + 63)/0.65

= 263 N

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